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6y^2+80y-56=0
a = 6; b = 80; c = -56;
Δ = b2-4ac
Δ = 802-4·6·(-56)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-88}{2*6}=\frac{-168}{12} =-14 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+88}{2*6}=\frac{8}{12} =2/3 $
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